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13500000133 = 38513505583
BaseRepresentation
bin11001001001010100…
…11010011110000101
31021211211122001200221
430210222122132011
5210122000001013
610111331504341
7655354051654
oct144452323605
937754561627
1013500000133
1157a8441a04
1227491580b1
131371b56b79
14920d2119b
155402ba08d
hex324a9a785

13500000133 has 4 divisors (see below), whose sum is σ = 13503509568. Its totient is φ = 13496490700.

The previous prime is 13500000131. The next prime is 13500000161. The reversal of 13500000133 is 33100000531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33100000531 = 132546153887.

It is a cyclic number.

It is not a de Polignac number, because 13500000133 - 21 = 13500000131 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13500000131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1748941 + ... + 1756642.

It is an arithmetic number, because the mean of its divisors is an integer number (3375877392).

Almost surely, 213500000133 is an apocalyptic number.

It is an amenable number.

13500000133 is a deficient number, since it is larger than the sum of its proper divisors (3509435).

13500000133 is an equidigital number, since it uses as much as digits as its factorization.

13500000133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3509434.

The product of its (nonzero) digits is 135, while the sum is 16.

Adding to 13500000133 its reverse (33100000531), we get a palindrome (46600000664).

The spelling of 13500000133 in words is "thirteen billion, five hundred million, one hundred thirty-three", and thus it is an aban number.

Divisors: 1 3851 3505583 13500000133