135000343 has 4 divisors (see below), whose sum is σ = 135431968. Its totient is φ = 134568720.

The previous prime is 135000329. The next prime is 135000361. The reversal of 135000343 is 343000531.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 135000343 - 2⁵ = 135000311 is a prime.

It is a super-2 number, since 2×135000343² = 36450185220235298, which contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 135000343.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (135000373) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 215343 + ... + 215968.

It is an arithmetic number, because the mean of its divisors is an integer number (33857992).

Almost surely, 2^135000343 is an apocalyptic number.

135000343 is a deficient number, since it is larger than the sum of its proper divisors (431625).

135000343 is an equidigital number, since it uses as much as digits as its factorization.

135000343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 431624.

The product of its (nonzero) digits is 540, while the sum is 19.

The square root of 135000343 is about 11618.9647989827. The cubic root of 135000343 is about 512.9932184632.

Adding to 135000343 its reverse (343000531), we get a palindrome (478000874).

The spelling of 135000343 in words is "one hundred thirty-five million, three hundred forty-three", and thus it is an aban number.