Base | Representation |
---|---|
bin | 1100010001110100100010… |
… | …1010001111001011011111 |
3 | 1202210121122012112222100222 |
4 | 3010131020222033023133 |
5 | 3232142104104234403 |
6 | 44413541444311555 |
7 | 2562236023115603 |
oct | 304351052171337 |
9 | 52717565488328 |
10 | 13500301243103 |
11 | 433549a110634 |
12 | 16205476a25bb |
13 | 76c0c434aa3c |
14 | 3495bd263503 |
15 | 186291972338 |
hex | c4748a8f2df |
13500301243103 has 2 divisors, whose sum is σ = 13500301243104. Its totient is φ = 13500301243102.
The previous prime is 13500301243073. The next prime is 13500301243109. The reversal of 13500301243103 is 30134210300531.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13500301243103 - 220 = 13500300194527 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13500301243109) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6750150621551 + 6750150621552.
It is an arithmetic number, because the mean of its divisors is an integer number (6750150621552).
Almost surely, 213500301243103 is an apocalyptic number.
13500301243103 is a deficient number, since it is larger than the sum of its proper divisors (1).
13500301243103 is an equidigital number, since it uses as much as digits as its factorization.
13500301243103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3240, while the sum is 26.
Adding to 13500301243103 its reverse (30134210300531), we get a palindrome (43634511543634).
The spelling of 13500301243103 in words is "thirteen trillion, five hundred billion, three hundred one million, two hundred forty-three thousand, one hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •