| Base | Representation |
|---|---|
| bin | 111110110111011100… |
| … | …1000001111010110000 |
| 3 | 110220110200122122000002 |
| 4 | 1331232321001322300 |
| 5 | 4202442113230000 |
| 6 | 142004205245132 |
| 7 | 12516351502166 |
| oct | 1755671017260 |
| 9 | 426420578002 |
| 10 | 135004430000 |
| 11 | 522895324a0 |
| 12 | 221b88637a8 |
| 13 | c96692490b |
| 14 | 6769da1236 |
| 15 | 37a23928d5 |
| hex | 1f6ee41eb0 |
135004430000 has 200 divisors, whose sum is σ = 359010392400. Its totient is φ = 48757120000.
The previous prime is 135004429991. The next prime is 135004430009. The reversal of 135004430000 is 34400531.
It is an interprime number because it is at equal distance from previous prime (135004429991) and next prime (135004430009).
It is a tau number, because it is divible by the number of its divisors (200).
It is a super-2 number, since 2×1350044300002 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is not an unprimeable number, because it can be changed into a prime (135004430009) by changing a digit.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 16385882 + ... + 16394118.
It is an arithmetic number, because the mean of its divisors is an integer number (1795051962).
Almost surely, 2135004430000 is an apocalyptic number.
135004430000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 135004430000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (179505196200).
135004430000 is an abundant number, since it is smaller than the sum of its proper divisors (224005962400).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
135004430000 is a wasteful number, since it uses less digits than its factorization.
135004430000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8425 (or 8404 counting only the distinct ones).
The product of its (nonzero) digits is 720, while the sum is 20.
Adding to 135004430000 its reverse (34400531), we get a palindrome (135038830531).
The spelling of 135004430000 in words is "one hundred thirty-five billion, four million, four hundred thirty thousand".
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