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13500551333 is a prime number
BaseRepresentation
bin11001001001011001…
…00001000010100101
31021211212200001210202
430210230201002211
5210122120120313
610111351400245
7655361535653
oct144454410245
937755601722
1013500551333
1157a8789045
122749383085
131371cbaa19
14921025dd3
15540378558
hex324b210a5

13500551333 has 2 divisors, whose sum is σ = 13500551334. Its totient is φ = 13500551332.

The previous prime is 13500551297. The next prime is 13500551341. The reversal of 13500551333 is 33315500531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7981992964 + 5518558369 = 89342^2 + 74287^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13500551333 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13500551296 and 13500551305.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13500551353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6750275666 + 6750275667.

It is an arithmetic number, because the mean of its divisors is an integer number (6750275667).

Almost surely, 213500551333 is an apocalyptic number.

It is an amenable number.

13500551333 is a deficient number, since it is larger than the sum of its proper divisors (1).

13500551333 is an equidigital number, since it uses as much as digits as its factorization.

13500551333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10125, while the sum is 29.

The spelling of 13500551333 in words is "thirteen billion, five hundred million, five hundred fifty-one thousand, three hundred thirty-three".