135015150114301 has 4 divisors (see below), whose sum is σ = 135130449133504. Its totient is φ = 134899851095100.

The previous prime is 135015150114263. The next prime is 135015150114307. The reversal of 135015150114301 is 103411051510531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-135015150114301 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (135015150114307) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 57649507845 + ... + 57649510186.

It is an arithmetic number, because the mean of its divisors is an integer number (33782612283376).

Almost surely, 2^{135015150114301} is an apocalyptic number.

It is an amenable number.

135015150114301 is a deficient number, since it is larger than the sum of its proper divisors (115299019203).

135015150114301 is a wasteful number, since it uses less digits than its factorization.

135015150114301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 115299019202.

The product of its (nonzero) digits is 4500, while the sum is 31.

The spelling of 135015150114301 in words is "one hundred thirty-five trillion, fifteen billion, one hundred fifty million, one hundred fourteen thousand, three hundred one".