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135018432011 is a prime number
BaseRepresentation
bin111110110111110111…
…0011100011000001011
3110220111200000000011002
41331233232130120023
54203004204311021
6142005425325215
712516611510321
oct1755756343013
9426450000132
10135018432011
1152296426401
122220149680b
13c9697b7c28
14676bba7d11
1537a370b50b
hex1f6fb9c60b

135018432011 has 2 divisors, whose sum is σ = 135018432012. Its totient is φ = 135018432010.

The previous prime is 135018431993. The next prime is 135018432013. The reversal of 135018432011 is 110234810531.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 135018432011 - 214 = 135018415627 is a prime.

Together with 135018432013, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (135018432013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67509216005 + 67509216006.

It is an arithmetic number, because the mean of its divisors is an integer number (67509216006).

Almost surely, 2135018432011 is an apocalyptic number.

135018432011 is a deficient number, since it is larger than the sum of its proper divisors (1).

135018432011 is an equidigital number, since it uses as much as digits as its factorization.

135018432011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2880, while the sum is 29.

The spelling of 135018432011 in words is "one hundred thirty-five billion, eighteen million, four hundred thirty-two thousand, eleven".