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135020140403 is a prime number
BaseRepresentation
bin111110110111111010…
…0111101011101110011
3110220111210012210121212
41331233310331131303
54203010123443103
6142005530110335
712516632154131
oct1755764753563
9426453183555
10135020140403
11522973929a5
1222201b7b3ab
13c969c65705
14676c0d0751
1537a39477d8
hex1f6fd3d773

135020140403 has 2 divisors, whose sum is σ = 135020140404. Its totient is φ = 135020140402.

The previous prime is 135020140327. The next prime is 135020140427. The reversal of 135020140403 is 304041020531.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 135020140403 - 28 = 135020140147 is a prime.

It is not a weakly prime, because it can be changed into another prime (135020140433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67510070201 + 67510070202.

It is an arithmetic number, because the mean of its divisors is an integer number (67510070202).

Almost surely, 2135020140403 is an apocalyptic number.

135020140403 is a deficient number, since it is larger than the sum of its proper divisors (1).

135020140403 is an equidigital number, since it uses as much as digits as its factorization.

135020140403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 23.

Adding to 135020140403 its reverse (304041020531), we get a palindrome (439061160934).

The spelling of 135020140403 in words is "one hundred thirty-five billion, twenty million, one hundred forty thousand, four hundred three".