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1350243130055 = 5270048626011
BaseRepresentation
bin10011101001100000110…
…000110001101011000111
311210002012202122220120212
4103221200300301223013
5134110244220130210
62512143152150035
7166360166144201
oct23514060615307
94702182586525
101350243130055
114806a9056476
1219982983831b
139a4343428b1
14494d02c7771
15251c9ce3805
hex13a60c31ac7

1350243130055 has 4 divisors (see below), whose sum is σ = 1620291756072. Its totient is φ = 1080194504040.

The previous prime is 1350243130051. The next prime is 1350243130091. The reversal of 1350243130055 is 5500313420531.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 1350243130055 - 22 = 1350243130051 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1350243130051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 135024313001 + ... + 135024313010.

It is an arithmetic number, because the mean of its divisors is an integer number (405072939018).

Almost surely, 21350243130055 is an apocalyptic number.

1350243130055 is a deficient number, since it is larger than the sum of its proper divisors (270048626017).

1350243130055 is an equidigital number, since it uses as much as digits as its factorization.

1350243130055 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 270048626016.

The product of its (nonzero) digits is 27000, while the sum is 32.

Adding to 1350243130055 its reverse (5500313420531), we get a palindrome (6850556550586).

The spelling of 1350243130055 in words is "one trillion, three hundred fifty billion, two hundred forty-three million, one hundred thirty thousand, fifty-five".

Divisors: 1 5 270048626011 1350243130055