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135024343 = 4316718803
BaseRepresentation
bin10000000110001…
…00111011010111
3100102001221120121
420003010323113
5234031234333
621222012411
73226454656
oct1003047327
9312057517
10135024343
116a243873
1239277107
1321c8767c
1413d0b19d
15bcc232d
hex80c4ed7

135024343 has 8 divisors (see below), whose sum is σ = 138999168. Its totient is φ = 131087544.

The previous prime is 135024311. The next prime is 135024361. The reversal of 135024343 is 343420531.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 135024343 - 25 = 135024311 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (135024143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2221 + ... + 16582.

It is an arithmetic number, because the mean of its divisors is an integer number (17374896).

Almost surely, 2135024343 is an apocalyptic number.

135024343 is a deficient number, since it is larger than the sum of its proper divisors (3974825).

135024343 is a wasteful number, since it uses less digits than its factorization.

135024343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19013.

The product of its (nonzero) digits is 4320, while the sum is 25.

The square root of 135024343 is about 11619.9975473319. The cubic root of 135024343 is about 513.0236161828.

Adding to 135024343 its reverse (343420531), we get a palindrome (478444874).

The spelling of 135024343 in words is "one hundred thirty-five million, twenty-four thousand, three hundred forty-three".

Divisors: 1 43 167 7181 18803 808529 3140101 135024343