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1350244423023 = 3450081474341
BaseRepresentation
bin10011101001100000110…
…101101101010101101111
311210002012212002121012120
4103221200311231111233
5134110300033014043
62512143240004023
7166360213140606
oct23514065552557
94702185077176
101350244423023
114806a9859941
1219982a160613
139a4346a6272
14494d0542a3d
15251c9e9b983
hex13a60d6d56f

1350244423023 has 4 divisors (see below), whose sum is σ = 1800325897368. Its totient is φ = 900162948680.

The previous prime is 1350244423001. The next prime is 1350244423037. The reversal of 1350244423023 is 3203244420531.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1350244423023 - 229 = 1349707552111 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1350244423043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 225040737168 + ... + 225040737173.

It is an arithmetic number, because the mean of its divisors is an integer number (450081474342).

Almost surely, 21350244423023 is an apocalyptic number.

1350244423023 is a deficient number, since it is larger than the sum of its proper divisors (450081474345).

1350244423023 is an equidigital number, since it uses as much as digits as its factorization.

1350244423023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 450081474344.

The product of its (nonzero) digits is 69120, while the sum is 33.

Adding to 1350244423023 its reverse (3203244420531), we get a palindrome (4553488843554).

The spelling of 1350244423023 in words is "one trillion, three hundred fifty billion, two hundred forty-four million, four hundred twenty-three thousand, twenty-three".

Divisors: 1 3 450081474341 1350244423023