Base | Representation |
---|---|
bin | 1100010001111100110010… |
… | …0000111111001110111101 |
3 | 1202210211100101010202020111 |
4 | 3010133030200333032331 |
5 | 3232211121413123010 |
6 | 44414545150550021 |
7 | 2562344604203653 |
oct | 304371440771675 |
9 | 52724311122214 |
10 | 13502513411005 |
11 | 43364248a1073 |
12 | 1620a64508311 |
13 | 76c38774c928 |
14 | 34974cd8add3 |
15 | 186370c9458a |
hex | c47cc83f3bd |
13502513411005 has 16 divisors (see below), whose sum is σ = 17161817734080. Its totient is φ = 10163230601472.
The previous prime is 13502513410999. The next prime is 13502513411047. The reversal of 13502513411005 is 50011431520531.
It is a cyclic number.
It is not a de Polignac number, because 13502513411005 - 25 = 13502513410973 is a prime.
It is a super-2 number, since 2×135025134110052 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 26052279 + ... + 26565508.
It is an arithmetic number, because the mean of its divisors is an integer number (1072613608380).
Almost surely, 213502513411005 is an apocalyptic number.
It is an amenable number.
13502513411005 is a deficient number, since it is larger than the sum of its proper divisors (3659304323075).
13502513411005 is a wasteful number, since it uses less digits than its factorization.
13502513411005 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 52620828.
The product of its (nonzero) digits is 9000, while the sum is 31.
Adding to 13502513411005 its reverse (50011431520531), we get a palindrome (63513944931536).
The spelling of 13502513411005 in words is "thirteen trillion, five hundred two billion, five hundred thirteen million, four hundred eleven thousand, five".
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