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135030304439 is a prime number
BaseRepresentation
bin111110111000001101…
…1101110111010110111
3110220112111100012001122
41331300123232322313
54203020224220224
6142010532014155
712520114435652
oct1756033567267
9426474305048
10135030304439
11522a20a5328
122220546135b
13c96c0b3b34
14676d5b8899
1537a47a415e
hex1f706eeeb7

135030304439 has 2 divisors, whose sum is σ = 135030304440. Its totient is φ = 135030304438.

The previous prime is 135030304369. The next prime is 135030304441. The reversal of 135030304439 is 934403030531.

It is a strong prime.

It is an emirp because it is prime and its reverse (934403030531) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 135030304439 - 232 = 130735337143 is a prime.

Together with 135030304441, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 135030304399 and 135030304408.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (135030304459) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67515152219 + 67515152220.

It is an arithmetic number, because the mean of its divisors is an integer number (67515152220).

Almost surely, 2135030304439 is an apocalyptic number.

135030304439 is a deficient number, since it is larger than the sum of its proper divisors (1).

135030304439 is an equidigital number, since it uses as much as digits as its factorization.

135030304439 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 58320, while the sum is 35.

The spelling of 135030304439 in words is "one hundred thirty-five billion, thirty million, three hundred four thousand, four hundred thirty-nine".