13503401096953 has 2 divisors, whose sum is σ = 13503401096954. Its totient is φ = 13503401096952.

The previous prime is 13503401096951. The next prime is 13503401096971. The reversal of 13503401096953 is 35969010430531.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13480852170384 + 22548926569 = 3671628^2 + 150163^2 .

It is an emirp because it is prime and its reverse (35969010430531) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13503401096953 - 2¹ = 13503401096951 is a prime.

Together with 13503401096951, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 13503401096897 and 13503401096906.

It is not a weakly prime, because it can be changed into another prime (13503401096951) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6751700548476 + 6751700548477.

It is an arithmetic number, because the mean of its divisors is an integer number (6751700548477).

Almost surely, 2^{13503401096953} is an apocalyptic number.

It is an amenable number.

13503401096953 is a deficient number, since it is larger than the sum of its proper divisors (1).

13503401096953 is an equidigital number, since it uses as much as digits as its factorization.

13503401096953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1312200, while the sum is 49.

The spelling of 13503401096953 in words is "thirteen trillion, five hundred three billion, four hundred one million, ninety-six thousand, nine hundred fifty-three".