Base | Representation |
---|---|
bin | 10011101001100110101… |
… | …111000000111101010111 |
3 | 11210002110202012200100211 |
4 | 103221212233000331113 |
5 | 134111000343103141 |
6 | 2512201131550251 |
7 | 166362523636165 |
oct | 23514657007527 |
9 | 4702422180324 |
10 | 1350343331671 |
11 | 48074a675424 |
12 | 1998572bb387 |
13 | 9a44c0270a9 |
14 | 494dd72c235 |
15 | 251d39d7d81 |
hex | 13a66bc0f57 |
1350343331671 has 2 divisors, whose sum is σ = 1350343331672. Its totient is φ = 1350343331670.
The previous prime is 1350343331629. The next prime is 1350343331681. The reversal of 1350343331671 is 1761333430531.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1350343331671 - 211 = 1350343329623 is a prime.
It is a super-2 number, since 2×13503433316712 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1350343331681) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675171665835 + 675171665836.
It is an arithmetic number, because the mean of its divisors is an integer number (675171665836).
Almost surely, 21350343331671 is an apocalyptic number.
1350343331671 is a deficient number, since it is larger than the sum of its proper divisors (1).
1350343331671 is an equidigital number, since it uses as much as digits as its factorization.
1350343331671 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 204120, while the sum is 40.
The spelling of 1350343331671 in words is "one trillion, three hundred fifty billion, three hundred forty-three million, three hundred thirty-one thousand, six hundred seventy-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •