Base | Representation |
---|---|
bin | 111110111000010101… |
… | …1010111000101111101 |
3 | 110220112210001022200122 |
4 | 1331300223113011331 |
5 | 4203022301314044 |
6 | 142011155504325 |
7 | 12520164320504 |
oct | 1756053270575 |
9 | 426483038618 |
10 | 135034401149 |
11 | 522a444323a |
12 | 222068b80a5 |
13 | c96cbb971b |
14 | 676dd6383b |
15 | 37a4d12dee |
hex | 1f70ad717d |
135034401149 has 2 divisors, whose sum is σ = 135034401150. Its totient is φ = 135034401148.
The previous prime is 135034401077. The next prime is 135034401157. The reversal of 135034401149 is 941104430531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 115239880900 + 19794520249 = 339470^2 + 140693^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-135034401149 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (135034401199) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67517200574 + 67517200575.
It is an arithmetic number, because the mean of its divisors is an integer number (67517200575).
Almost surely, 2135034401149 is an apocalyptic number.
It is an amenable number.
135034401149 is a deficient number, since it is larger than the sum of its proper divisors (1).
135034401149 is an equidigital number, since it uses as much as digits as its factorization.
135034401149 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 25920, while the sum is 35.
The spelling of 135034401149 in words is "one hundred thirty-five billion, thirty-four million, four hundred one thousand, one hundred forty-nine".
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