Base | Representation |
---|---|
bin | 10011101001100111001… |
… | …100100011001101011101 |
3 | 11210002111021210001000222 |
4 | 103221213030203031131 |
5 | 134111004333333031 |
6 | 2512202005531125 |
7 | 166362646514036 |
oct | 23514714431535 |
9 | 4702437701028 |
10 | 1350351074141 |
11 | 480753a83463 |
12 | 199859a13aa5 |
13 | 9a450808234 |
14 | 49500785a8d |
15 | 251d4516e7b |
hex | 13a6732335d |
1350351074141 has 4 divisors (see below), whose sum is σ = 1409061990432. Its totient is φ = 1291640157852.
The previous prime is 1350351074117. The next prime is 1350351074143. The reversal of 1350351074141 is 1414701530531.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1350351074141 - 234 = 1333171204957 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1350351074143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29355458111 + ... + 29355458156.
It is an arithmetic number, because the mean of its divisors is an integer number (352265497608).
Almost surely, 21350351074141 is an apocalyptic number.
It is an amenable number.
1350351074141 is a deficient number, since it is larger than the sum of its proper divisors (58710916291).
1350351074141 is an equidigital number, since it uses as much as digits as its factorization.
1350351074141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 58710916290.
The product of its (nonzero) digits is 25200, while the sum is 35.
The spelling of 1350351074141 in words is "one trillion, three hundred fifty billion, three hundred fifty-one million, seventy-four thousand, one hundred forty-one".
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