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13504154423 is a prime number
BaseRepresentation
bin11001001001110100…
…10000101100110111
31021212010110010022112
430210322100230313
5210124030420143
610112000521235
7655434263414
oct144472205467
937763403275
1013504154423
1157aa81a101
12274a62021b
13137297ca26
149216c310b
1554083ae18
hex324e90b37

13504154423 has 2 divisors, whose sum is σ = 13504154424. Its totient is φ = 13504154422.

The previous prime is 13504154401. The next prime is 13504154431. The reversal of 13504154423 is 32445140531.

13504154423 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13504154423 - 224 = 13487377207 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13504154423.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13504154483) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6752077211 + 6752077212.

It is an arithmetic number, because the mean of its divisors is an integer number (6752077212).

Almost surely, 213504154423 is an apocalyptic number.

13504154423 is a deficient number, since it is larger than the sum of its proper divisors (1).

13504154423 is an equidigital number, since it uses as much as digits as its factorization.

13504154423 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 28800, while the sum is 32.

Adding to 13504154423 its reverse (32445140531), we get a palindrome (45949294954).

The spelling of 13504154423 in words is "thirteen billion, five hundred four million, one hundred fifty-four thousand, four hundred twenty-three".