1350430255345 has 4 divisors (see below), whose sum is σ = 1620516306420. Its totient is φ = 1080344204272.

The previous prime is 1350430255313. The next prime is 1350430255373. The reversal of 1350430255345 is 5435520340531.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 215191148769 + 1135239106576 = 463887^2 + 1065476^2 .

It is a cyclic number.

It is not a de Polignac number, because 1350430255345 - 2⁵ = 1350430255313 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1350430255298 and 1350430255307.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 135043025530 + ... + 135043025539.

It is an arithmetic number, because the mean of its divisors is an integer number (405129076605).

Almost surely, 2^{1350430255345} is an apocalyptic number.

It is an amenable number.

1350430255345 is a deficient number, since it is larger than the sum of its proper divisors (270086051075).

1350430255345 is an equidigital number, since it uses as much as digits as its factorization.

1350430255345 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 270086051074.

The product of its (nonzero) digits is 540000, while the sum is 40.

Adding to 1350430255345 its reverse (5435520340531), we get a palindrome (6785950595876).

The spelling of 1350430255345 in words is "one trillion, three hundred fifty billion, four hundred thirty million, two hundred fifty-five thousand, three hundred forty-five".