13504334401445 has 4 divisors (see below), whose sum is σ = 16205201281740. Its totient is φ = 10803467521152.

The previous prime is 13504334401321. The next prime is 13504334401457. The reversal of 13504334401445 is 54410443340531.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2532830871169 + 10971503530276 = 1591487^2 + 3312326^2 .

It is a cyclic number.

It is not a de Polignac number, because 13504334401445 - 2²² = 13504330207141 is a prime.

It is a Curzon number.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1350433440140 + ... + 1350433440149.

It is an arithmetic number, because the mean of its divisors is an integer number (4051300320435).

Almost surely, 2^{13504334401445} is an apocalyptic number.

It is an amenable number.

13504334401445 is a deficient number, since it is larger than the sum of its proper divisors (2700866880295).

13504334401445 is an equidigital number, since it uses as much as digits as its factorization.

13504334401445 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2700866880294.

The product of its (nonzero) digits is 691200, while the sum is 41.

Adding to 13504334401445 its reverse (54410443340531), we get a palindrome (67914777741976).

The spelling of 13504334401445 in words is "thirteen trillion, five hundred four billion, three hundred thirty-four million, four hundred one thousand, four hundred forty-five".