13504343151541 has 4 divisors (see below), whose sum is σ = 14732010710784. Its totient is φ = 12276675592300.

The previous prime is 13504343151539. The next prime is 13504343151613. The reversal of 13504343151541 is 14515134340531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13504343151541 - 2¹ = 13504343151539 is a prime.

It is a super-3 number, since 3×13504343151541³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13504343151494 and 13504343151503.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13504343151521) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 613833779605 + ... + 613833779626.

It is an arithmetic number, because the mean of its divisors is an integer number (3683002677696).

Almost surely, 2^{13504343151541} is an apocalyptic number.

13504343151541 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

13504343151541 is a deficient number, since it is larger than the sum of its proper divisors (1227667559243).

13504343151541 is a wasteful number, since it uses less digits than its factorization.

13504343151541 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1227667559242.

The product of its (nonzero) digits is 216000, while the sum is 40.

The spelling of 13504343151541 in words is "thirteen trillion, five hundred four billion, three hundred forty-three million, one hundred fifty-one thousand, five hundred forty-one".