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1350441625103 = 1373983570011
BaseRepresentation
bin10011101001101100100…
…101111110011000001111
311210002201121011111121022
4103221230211332120033
5134111201024000403
62512215002424355
7166365126263024
oct23515445763017
94702647144538
101350441625103
114807a010076a
121998842020bb
139a4664c0b9c
144950c7d754b
15251dc451d38
hex13a6c97e60f

1350441625103 has 4 divisors (see below), whose sum is σ = 1351425196488. Its totient is φ = 1349458053720.

The previous prime is 1350441625097. The next prime is 1350441625111. The reversal of 1350441625103 is 3015261440531.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1350441625103 - 216 = 1350441559567 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1350441625303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 491783633 + ... + 491786378.

It is an arithmetic number, because the mean of its divisors is an integer number (337856299122).

Almost surely, 21350441625103 is an apocalyptic number.

1350441625103 is a deficient number, since it is larger than the sum of its proper divisors (983571385).

1350441625103 is an equidigital number, since it uses as much as digits as its factorization.

1350441625103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 983571384.

The product of its (nonzero) digits is 43200, while the sum is 35.

The spelling of 1350441625103 in words is "one trillion, three hundred fifty billion, four hundred forty-one million, six hundred twenty-five thousand, one hundred three".

Divisors: 1 1373 983570011 1350441625103