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135048164471 = 1112277105861
BaseRepresentation
bin111110111000101111…
…1110111010001110111
3110220120201221120102022
41331301133313101313
54203034312230341
6142012410503355
712520422313013
oct1756137672167
9426521846368
10135048164471
1152301193890
122220b434b5b
13c9729c81bc
146771b07543
1537a6130e4b
hex1f717f7477

135048164471 has 4 divisors (see below), whose sum is σ = 147325270344. Its totient is φ = 122771058600.

The previous prime is 135048164443. The next prime is 135048164479. The reversal of 135048164471 is 174461840531.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-135048164471 is a prime.

It is a super-3 number, since 3×1350481644713 (a number of 34 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (135048164479) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6138552920 + ... + 6138552941.

It is an arithmetic number, because the mean of its divisors is an integer number (36831317586).

Almost surely, 2135048164471 is an apocalyptic number.

135048164471 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

135048164471 is a deficient number, since it is larger than the sum of its proper divisors (12277105873).

135048164471 is a wasteful number, since it uses less digits than its factorization.

135048164471 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12277105872.

The product of its (nonzero) digits is 322560, while the sum is 44.

The spelling of 135048164471 in words is "one hundred thirty-five billion, forty-eight million, one hundred sixty-four thousand, four hundred seventy-one".

Divisors: 1 11 12277105861 135048164471