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135053201341 = 672015719423
BaseRepresentation
bin111110111000111001…
…1000100111110111101
3110220121002102110201001
41331301303010332331
54203042104420331
6142013110450301
712520513161532
oct1756163047675
9426532373631
10135053201341
1152304014093
1222211063991
13c973a6c9b6
146772658d89
1537a67c8561
hex1f71cc4fbd

135053201341 has 4 divisors (see below), whose sum is σ = 137068920832. Its totient is φ = 133037481852.

The previous prime is 135053201333. The next prime is 135053201377. The reversal of 135053201341 is 143102350531.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 135053201341 - 23 = 135053201333 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (135053201441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1007859645 + ... + 1007859778.

It is an arithmetic number, because the mean of its divisors is an integer number (34267230208).

Almost surely, 2135053201341 is an apocalyptic number.

It is an amenable number.

135053201341 is a deficient number, since it is larger than the sum of its proper divisors (2015719491).

135053201341 is an equidigital number, since it uses as much as digits as its factorization.

135053201341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2015719490.

The product of its (nonzero) digits is 5400, while the sum is 28.

Adding to 135053201341 its reverse (143102350531), we get a palindrome (278155551872).

The spelling of 135053201341 in words is "one hundred thirty-five billion, fifty-three million, two hundred one thousand, three hundred forty-one".

Divisors: 1 67 2015719423 135053201341