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135059200277 is a prime number
BaseRepresentation
bin111110111001000100…
…1111101100100010101
3110220121111201020200212
41331302021331210111
54203100123402102
6142013443215205
712520615155251
oct1756211754425
9426544636625
10135059200277
1152307441191
1222213077505
13c975090371
14677337b261
1537a70b0c52
hex1f7227d915

135059200277 has 2 divisors, whose sum is σ = 135059200278. Its totient is φ = 135059200276.

The previous prime is 135059200273. The next prime is 135059200279. The reversal of 135059200277 is 772002950531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 86770895761 + 48288304516 = 294569^2 + 219746^2 .

It is a cyclic number.

It is not a de Polignac number, because 135059200277 - 22 = 135059200273 is a prime.

Together with 135059200279, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (135059200271) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67529600138 + 67529600139.

It is an arithmetic number, because the mean of its divisors is an integer number (67529600139).

Almost surely, 2135059200277 is an apocalyptic number.

It is an amenable number.

135059200277 is a deficient number, since it is larger than the sum of its proper divisors (1).

135059200277 is an equidigital number, since it uses as much as digits as its factorization.

135059200277 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 132300, while the sum is 41.

The spelling of 135059200277 in words is "one hundred thirty-five billion, fifty-nine million, two hundred thousand, two hundred seventy-seven".