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1350626819 is a prime number
BaseRepresentation
bin101000010000000…
…1110111000000011
310111010102221200112
41100200032320003
510231230024234
6342004341535
745320065343
oct12040167003
93433387615
101350626819
11633436a13
123183a48ab
13186a82789
14cb53cd23
157d890ace
hex5080ee03

1350626819 has 2 divisors, whose sum is σ = 1350626820. Its totient is φ = 1350626818.

The previous prime is 1350626813. The next prime is 1350626821. The reversal of 1350626819 is 9186260531.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1350626819 is a prime.

It is a super-2 number, since 2×13506268192 = 3648385608404117522, which contains 22 as substring.

Together with 1350626821, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1350626813) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675313409 + 675313410.

It is an arithmetic number, because the mean of its divisors is an integer number (675313410).

Almost surely, 21350626819 is an apocalyptic number.

1350626819 is a deficient number, since it is larger than the sum of its proper divisors (1).

1350626819 is an equidigital number, since it uses as much as digits as its factorization.

1350626819 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 77760, while the sum is 41.

The square root of 1350626819 is about 36750.8750780168. The cubic root of 1350626819 is about 1105.3804765279.

The spelling of 1350626819 in words is "one billion, three hundred fifty million, six hundred twenty-six thousand, eight hundred nineteen".