Base | Representation |
---|---|
bin | 10000000110011… |
… | …11101101010111 |
3 | 100102011012011011 |
4 | 20003033231113 |
5 | 234034143003 |
6 | 21222553051 |
7 | 3230030503 |
oct | 1003175527 |
9 | 312135134 |
10 | 135068503 |
11 | 6a273a69 |
12 | 39298787 |
13 | 21ca17bb |
14 | 13d1d303 |
15 | bcd046d |
hex | 80cfb57 |
135068503 has 2 divisors, whose sum is σ = 135068504. Its totient is φ = 135068502.
The previous prime is 135068497. The next prime is 135068509. The reversal of 135068503 is 305860531.
It is a balanced prime because it is at equal distance from previous prime (135068497) and next prime (135068509).
It is an emirp because it is prime and its reverse (305860531) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 135068503 - 25 = 135068471 is a prime.
It is a super-2 number, since 2×1350685032 = 36487001005322018, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (135068509) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67534251 + 67534252.
It is an arithmetic number, because the mean of its divisors is an integer number (67534252).
Almost surely, 2135068503 is an apocalyptic number.
135068503 is a deficient number, since it is larger than the sum of its proper divisors (1).
135068503 is an equidigital number, since it uses as much as digits as its factorization.
135068503 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10800, while the sum is 31.
The square root of 135068503 is about 11621.8975645116. The cubic root of 135068503 is about 513.0795385768.
The spelling of 135068503 in words is "one hundred thirty-five million, sixty-eight thousand, five hundred three".
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