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135074328293 is a prime number
BaseRepresentation
bin111110111001100001…
…1101010111011100101
3110220122120011211102202
41331303003222323211
54203113012001133
6142015143344245
712521160563252
oct1756303527345
9426576154382
10135074328293
1152314a34083
1222218152085
13c978259058
146775398429
1537a859d2e8
hex1f730eaee5

135074328293 has 2 divisors, whose sum is σ = 135074328294. Its totient is φ = 135074328292.

The previous prime is 135074328281. The next prime is 135074328329. The reversal of 135074328293 is 392823470531.

Together with next prime (135074328329) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 122579112769 + 12495215524 = 350113^2 + 111782^2 .

It is a cyclic number.

It is not a de Polignac number, because 135074328293 - 224 = 135057551077 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (135074327293) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67537164146 + 67537164147.

It is an arithmetic number, because the mean of its divisors is an integer number (67537164147).

Almost surely, 2135074328293 is an apocalyptic number.

It is an amenable number.

135074328293 is a deficient number, since it is larger than the sum of its proper divisors (1).

135074328293 is an equidigital number, since it uses as much as digits as its factorization.

135074328293 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1088640, while the sum is 47.

The spelling of 135074328293 in words is "one hundred thirty-five billion, seventy-four million, three hundred twenty-eight thousand, two hundred ninety-three".