Base | Representation |
---|---|
bin | 1100010010010101011110… |
… | …0010100011011100001111 |
3 | 1202211110110020210002200122 |
4 | 3010211113202203130033 |
5 | 3232313210022244100 |
6 | 44422002535215155 |
7 | 2563001050234154 |
oct | 304452742433417 |
9 | 52743406702618 |
10 | 13509140821775 |
11 | 43392158a1955 |
12 | 16221b3b174bb |
13 | 76cba27c0871 |
14 | 349bbb23a22b |
15 | 18660ca11985 |
hex | c49578a370f |
13509140821775 has 12 divisors (see below), whose sum is σ = 16751385322632. Its totient is φ = 10807279945440.
The previous prime is 13509140821717. The next prime is 13509140821793. The reversal of 13509140821775 is 57712804190531.
13509140821775 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a de Polignac number, because none of the positive numbers 2k-13509140821775 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 10897589 + ... + 12073761.
It is an arithmetic number, because the mean of its divisors is an integer number (1395948776886).
Almost surely, 213509140821775 is an apocalyptic number.
13509140821775 is a deficient number, since it is larger than the sum of its proper divisors (3242244500857).
13509140821775 is a wasteful number, since it uses less digits than its factorization.
13509140821775 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1635610 (or 1635605 counting only the distinct ones).
The product of its (nonzero) digits is 2116800, while the sum is 53.
The spelling of 13509140821775 in words is "thirteen trillion, five hundred nine billion, one hundred forty million, eight hundred twenty-one thousand, seven hundred seventy-five".
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