Search a number
-
+
13510043149 is a prime number
BaseRepresentation
bin11001001010100001…
…01110011000001101
31021212112112022010111
430211100232120031
5210132032340044
610112331040021
7655535320621
oct144520563015
937775468114
1013510043149
115803081419
1227505a0011
131373c62195
149223b7181
15541100b34
hex32542e60d

13510043149 has 2 divisors, whose sum is σ = 13510043150. Its totient is φ = 13510043148.

The previous prime is 13510043143. The next prime is 13510043159. The reversal of 13510043149 is 94134001531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13275187524 + 234855625 = 115218^2 + 15325^2 .

It is a cyclic number.

It is not a de Polignac number, because 13510043149 - 213 = 13510034957 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13510043149.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13510043143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6755021574 + 6755021575.

It is an arithmetic number, because the mean of its divisors is an integer number (6755021575).

Almost surely, 213510043149 is an apocalyptic number.

It is an amenable number.

13510043149 is a deficient number, since it is larger than the sum of its proper divisors (1).

13510043149 is an equidigital number, since it uses as much as digits as its factorization.

13510043149 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6480, while the sum is 31.

The spelling of 13510043149 in words is "thirteen billion, five hundred ten million, forty-three thousand, one hundred forty-nine".