Base | Representation |
---|---|
bin | 11001001010100001… |
… | …01110011000000111 |
3 | 1021212112112022010021 |
4 | 30211100232120013 |
5 | 210132032340033 |
6 | 10112331040011 |
7 | 655535320612 |
oct | 144520563007 |
9 | 37775468107 |
10 | 13510043143 |
11 | 5803081413 |
12 | 27505a0007 |
13 | 1373c6218c |
14 | 9223b7179 |
15 | 541100b2d |
hex | 32542e607 |
13510043143 has 2 divisors, whose sum is σ = 13510043144. Its totient is φ = 13510043142.
The previous prime is 13510043051. The next prime is 13510043149. The reversal of 13510043143 is 34134001531.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13510043143 - 217 = 13509912071 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13510043149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6755021571 + 6755021572.
It is an arithmetic number, because the mean of its divisors is an integer number (6755021572).
Almost surely, 213510043143 is an apocalyptic number.
13510043143 is a deficient number, since it is larger than the sum of its proper divisors (1).
13510043143 is an equidigital number, since it uses as much as digits as its factorization.
13510043143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 13510043143 its reverse (34134001531), we get a palindrome (47644044674).
The spelling of 13510043143 in words is "thirteen billion, five hundred ten million, forty-three thousand, one hundred forty-three".
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