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13510043143 is a prime number
BaseRepresentation
bin11001001010100001…
…01110011000000111
31021212112112022010021
430211100232120013
5210132032340033
610112331040011
7655535320612
oct144520563007
937775468107
1013510043143
115803081413
1227505a0007
131373c6218c
149223b7179
15541100b2d
hex32542e607

13510043143 has 2 divisors, whose sum is σ = 13510043144. Its totient is φ = 13510043142.

The previous prime is 13510043051. The next prime is 13510043149. The reversal of 13510043143 is 34134001531.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13510043143 - 217 = 13509912071 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13510043149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6755021571 + 6755021572.

It is an arithmetic number, because the mean of its divisors is an integer number (6755021572).

Almost surely, 213510043143 is an apocalyptic number.

13510043143 is a deficient number, since it is larger than the sum of its proper divisors (1).

13510043143 is an equidigital number, since it uses as much as digits as its factorization.

13510043143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 13510043143 its reverse (34134001531), we get a palindrome (47644044674).

The spelling of 13510043143 in words is "thirteen billion, five hundred ten million, forty-three thousand, one hundred forty-three".