Base | Representation |
---|---|
bin | 111110111010011000… |
… | …1110011001111001001 |
3 | 110220201120111120102211 |
4 | 1331310301303033021 |
5 | 4203142404320103 |
6 | 142022054225121 |
7 | 12521661144040 |
oct | 1756461631711 |
9 | 426646446384 |
10 | 135103198153 |
11 | 5232a262470 |
12 | 222259551a1 |
13 | c981226801 |
14 | 6779151557 |
15 | 37aada236d |
hex | 1f74c733c9 |
135103198153 has 8 divisors (see below), whose sum is σ = 168440351040. Its totient is φ = 105275219280.
The previous prime is 135103198079. The next prime is 135103198183. The reversal of 135103198153 is 351891301531.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 135103198153 - 217 = 135103067081 is a prime.
It is a super-2 number, since 2×1351031981532 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (135103198183) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 877293418 + ... + 877293571.
It is an arithmetic number, because the mean of its divisors is an integer number (21055043880).
Almost surely, 2135103198153 is an apocalyptic number.
It is an amenable number.
135103198153 is a deficient number, since it is larger than the sum of its proper divisors (33337152887).
135103198153 is a wasteful number, since it uses less digits than its factorization.
135103198153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1754587007.
The product of its (nonzero) digits is 48600, while the sum is 40.
Adding to 135103198153 its reverse (351891301531), we get a palindrome (486994499684).
The spelling of 135103198153 in words is "one hundred thirty-five billion, one hundred three million, one hundred ninety-eight thousand, one hundred fifty-three".
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