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135110131143 = 3133464362337
BaseRepresentation
bin111110111010100110…
…0001111110111000111
3110220202001112210201020
41331311030033313013
54203201143144033
6142022503002223
712522104110611
oct1756514176707
9426661483636
10135110131143
1152333168309
1222228139373
13c9827b3380
14677a037db1
1537ab7c16b3
hex1f7530fdc7

135110131143 has 8 divisors (see below), whose sum is σ = 194004290928. Its totient is φ = 83144696064.

The previous prime is 135110131133. The next prime is 135110131147. The reversal of 135110131143 is 341131011531.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 135110131143 - 25 = 135110131111 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (135110131147) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1732181130 + ... + 1732181207.

It is an arithmetic number, because the mean of its divisors is an integer number (24250536366).

Almost surely, 2135110131143 is an apocalyptic number.

135110131143 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

135110131143 is a deficient number, since it is larger than the sum of its proper divisors (58894159785).

135110131143 is a wasteful number, since it uses less digits than its factorization.

135110131143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3464362353.

The product of its (nonzero) digits is 540, while the sum is 24.

Adding to 135110131143 its reverse (341131011531), we get a palindrome (476241142674).

The spelling of 135110131143 in words is "one hundred thirty-five billion, one hundred ten million, one hundred thirty-one thousand, one hundred forty-three".

Divisors: 1 3 13 39 3464362337 10393087011 45036710381 135110131143