135111224556301 has 4 divisors (see below), whose sum is σ = 154412828064352. Its totient is φ = 115809621048252.

The previous prime is 135111224556289. The next prime is 135111224556307. The reversal of 135111224556301 is 103655422111531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 135111224556301 - 2¹³ = 135111224548109 is a prime.

It is a super-2 number, since 2×135111224556301² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (135111224556307) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9650801754015 + ... + 9650801754028.

It is an arithmetic number, because the mean of its divisors is an integer number (38603207016088).

Almost surely, 2^{135111224556301} is an apocalyptic number.

It is an amenable number.

135111224556301 is a deficient number, since it is larger than the sum of its proper divisors (19301603508051).

135111224556301 is an equidigital number, since it uses as much as digits as its factorization.

135111224556301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19301603508050.

The product of its (nonzero) digits is 108000, while the sum is 40.

Adding to 135111224556301 its reverse (103655422111531), we get a palindrome (238766646667832).

The spelling of 135111224556301 in words is "one hundred thirty-five trillion, one hundred eleven billion, two hundred twenty-four million, five hundred fifty-six thousand, three hundred one".