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13511235431 is a prime number
BaseRepresentation
bin11001001010101010…
…10001011101100111
31021212121202212122002
430211111101131213
5210132334013211
610112412355515
7655551414641
oct144525213547
937777685562
1013511235431
115803816181
122750a75b9b
13137428ba85
14922607891
1554128903b
hex325551767

13511235431 has 2 divisors, whose sum is σ = 13511235432. Its totient is φ = 13511235430.

The previous prime is 13511235421. The next prime is 13511235433. The reversal of 13511235431 is 13453211531.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13511235431 - 226 = 13444126567 is a prime.

It is a super-2 number, since 2×135112354312 (a number of 21 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 13511235433, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13511235394 and 13511235403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13511235433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6755617715 + 6755617716.

It is an arithmetic number, because the mean of its divisors is an integer number (6755617716).

Almost surely, 213511235431 is an apocalyptic number.

13511235431 is a deficient number, since it is larger than the sum of its proper divisors (1).

13511235431 is an equidigital number, since it uses as much as digits as its factorization.

13511235431 is an evil number, because the sum of its binary digits is even.

The product of its digits is 5400, while the sum is 29.

Adding to 13511235431 its reverse (13453211531), we get a palindrome (26964446962).

The spelling of 13511235431 in words is "thirteen billion, five hundred eleven million, two hundred thirty-five thousand, four hundred thirty-one".