Base | Representation |
---|---|
bin | 10011101010010110111… |
… | …110010011010001010111 |
3 | 11210011120011002001211020 |
4 | 103222112332103101113 |
5 | 134114130034121312 |
6 | 2512413322212223 |
7 | 166421551662651 |
oct | 23522676232127 |
9 | 4704504061736 |
10 | 1351152645207 |
11 | 481025497692 |
12 | 199a42354073 |
13 | 9a54a8bb241 |
14 | 49578ddd6d1 |
15 | 2522ea9e78c |
hex | 13a96f93457 |
1351152645207 has 4 divisors (see below), whose sum is σ = 1801536860280. Its totient is φ = 900768430136.
The previous prime is 1351152645173. The next prime is 1351152645317. The reversal of 1351152645207 is 7025462511531.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1351152645207 - 219 = 1351152120919 is a prime.
It is a super-2 number, since 2×13511526452072 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1351152665207) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 225192107532 + ... + 225192107537.
It is an arithmetic number, because the mean of its divisors is an integer number (450384215070).
Almost surely, 21351152645207 is an apocalyptic number.
1351152645207 is a deficient number, since it is larger than the sum of its proper divisors (450384215073).
1351152645207 is an equidigital number, since it uses as much as digits as its factorization.
1351152645207 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 450384215072.
The product of its (nonzero) digits is 252000, while the sum is 42.
The spelling of 1351152645207 in words is "one trillion, three hundred fifty-one billion, one hundred fifty-two million, six hundred forty-five thousand, two hundred seven".
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