Base | Representation |
---|---|
bin | 111110111010110000… |
… | …0000111110011111111 |
3 | 110220202102100111100221 |
4 | 1331311200013303333 |
5 | 4203204011403210 |
6 | 142023210402211 |
7 | 12522166310062 |
oct | 1756540076377 |
9 | 426672314327 |
10 | 135115341055 |
11 | 523360a6622 |
12 | 22229a30367 |
13 | c9838b8866 |
14 | 677a9d28d9 |
15 | 37abea01da |
hex | 1f75807cff |
135115341055 has 4 divisors (see below), whose sum is σ = 162138409272. Its totient is φ = 108092272840.
The previous prime is 135115341047. The next prime is 135115341061. The reversal of 135115341055 is 550143511531.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 550143511531 = 20147 ⋅27306473.
It is not a de Polignac number, because 135115341055 - 23 = 135115341047 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 135115341055.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13511534101 + ... + 13511534110.
It is an arithmetic number, because the mean of its divisors is an integer number (40534602318).
Almost surely, 2135115341055 is an apocalyptic number.
135115341055 is a deficient number, since it is larger than the sum of its proper divisors (27023068217).
135115341055 is an equidigital number, since it uses as much as digits as its factorization.
135115341055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 27023068216.
The product of its (nonzero) digits is 22500, while the sum is 34.
Adding to 135115341055 its reverse (550143511531), we get a palindrome (685258852586).
The spelling of 135115341055 in words is "one hundred thirty-five billion, one hundred fifteen million, three hundred forty-one thousand, fifty-five".
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