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1351331040053 is a prime number
BaseRepresentation
bin10011101010100001100…
…110110100101100110101
311210012000120202110112202
4103222201212310230311
5134120011221240203
62512443133554245
7166426146214361
oct23524146645465
94705016673482
101351331040053
11481107163345
12199a92045985
139a57884c617
144959499a2a1
152524058c388
hex13aa19b4b35

1351331040053 has 2 divisors, whose sum is σ = 1351331040054. Its totient is φ = 1351331040052.

The previous prime is 1351331040041. The next prime is 1351331040151. The reversal of 1351331040053 is 3500401331531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1313002014769 + 38329025284 = 1145863^2 + 195778^2 .

It is a cyclic number.

It is not a de Polignac number, because 1351331040053 - 232 = 1347036072757 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1351331039998 and 1351331040025.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1351331040953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675665520026 + 675665520027.

It is an arithmetic number, because the mean of its divisors is an integer number (675665520027).

Almost surely, 21351331040053 is an apocalyptic number.

It is an amenable number.

1351331040053 is a deficient number, since it is larger than the sum of its proper divisors (1).

1351331040053 is an equidigital number, since it uses as much as digits as its factorization.

1351331040053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8100, while the sum is 29.

Adding to 1351331040053 its reverse (3500401331531), we get a palindrome (4851732371584).

The spelling of 1351331040053 in words is "one trillion, three hundred fifty-one billion, three hundred thirty-one million, forty thousand, fifty-three".