1351331040151 has 2 divisors, whose sum is σ = 1351331040152. Its totient is φ = 1351331040150.

The previous prime is 1351331040053. The next prime is 1351331040167. The reversal of 1351331040151 is 1510401331531.

It is a strong prime.

It is an emirp because it is prime and its reverse (1510401331531) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1351331040151 - 2¹¹ = 1351331038103 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1351331040181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675665520075 + 675665520076.

It is an arithmetic number, because the mean of its divisors is an integer number (675665520076).

Almost surely, 2^{1351331040151} is an apocalyptic number.

1351331040151 is a deficient number, since it is larger than the sum of its proper divisors (1).

1351331040151 is an equidigital number, since it uses as much as digits as its factorization.

1351331040151 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2700, while the sum is 28.

Adding to 1351331040151 its reverse (1510401331531), we get a palindrome (2861732371682).

The spelling of 1351331040151 in words is "one trillion, three hundred fifty-one billion, three hundred thirty-one million, forty thousand, one hundred fifty-one".