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13513431241 = 26177516233
BaseRepresentation
bin11001001010111011…
…01001100011001001
31021212202220102201101
430211131221203021
5210133414244431
610112531421401
7655606161502
oct144535514311
937782812641
1013513431241
115804a859a2
122751754861
13137487a37b
14922a19ba9
1554156e961
hex3257698c9

13513431241 has 4 divisors (see below), whose sum is σ = 13513973652. Its totient is φ = 13512888832.

The previous prime is 13513431233. The next prime is 13513431251. The reversal of 13513431241 is 14213431531.

13513431241 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 14213431531 = 131093340887.

It can be written as a sum of positive squares in 2 ways, for example, as 12494544841 + 1018886400 = 111779^2 + 31920^2 .

It is a cyclic number.

It is not a de Polignac number, because 13513431241 - 23 = 13513431233 is a prime.

It is a super-2 number, since 2×135134312412 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13513431251) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 231940 + ... + 284293.

It is an arithmetic number, because the mean of its divisors is an integer number (3378493413).

Almost surely, 213513431241 is an apocalyptic number.

It is an amenable number.

13513431241 is a deficient number, since it is larger than the sum of its proper divisors (542411).

13513431241 is an equidigital number, since it uses as much as digits as its factorization.

13513431241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 542410.

The product of its digits is 4320, while the sum is 28.

Adding to 13513431241 its reverse (14213431531), we get a palindrome (27726862772).

It can be divided in two parts, 135134 and 31241, that added together give a cube (166375 = 553).

The spelling of 13513431241 in words is "thirteen billion, five hundred thirteen million, four hundred thirty-one thousand, two hundred forty-one".

Divisors: 1 26177 516233 13513431241