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1351368536381 is a prime number
BaseRepresentation
bin10011101010100011110…
…101110111000100111101
311210012010012022110211122
4103222203311313010331
5134120100321131011
62512450553400325
7166430113014203
oct23524365670475
94705105273748
101351368536381
11481126343946
12199aa27090a5
139a58354a6b6
144959995b073
15252439e73db
hex13aa3d7713d

1351368536381 has 2 divisors, whose sum is σ = 1351368536382. Its totient is φ = 1351368536380.

The previous prime is 1351368536377. The next prime is 1351368536383. The reversal of 1351368536381 is 1836358631531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 971870647225 + 379497889156 = 985835^2 + 616034^2 .

It is a cyclic number.

It is not a de Polignac number, because 1351368536381 - 22 = 1351368536377 is a prime.

It is a super-2 number, since 2×13513685363812 (a number of 25 digits) contains 22 as substring.

Together with 1351368536383, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1351368536383) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675684268190 + 675684268191.

It is an arithmetic number, because the mean of its divisors is an integer number (675684268191).

Almost surely, 21351368536381 is an apocalyptic number.

It is an amenable number.

1351368536381 is a deficient number, since it is larger than the sum of its proper divisors (1).

1351368536381 is an equidigital number, since it uses as much as digits as its factorization.

1351368536381 is an evil number, because the sum of its binary digits is even.

The product of its digits is 4665600, while the sum is 53.

The spelling of 1351368536381 in words is "one trillion, three hundred fifty-one billion, three hundred sixty-eight million, five hundred thirty-six thousand, three hundred eighty-one".