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13520113151 = 27487491873
BaseRepresentation
bin11001001011101110…
…01000110111111111
31021220020110220120112
430211313020313333
5210142122110101
610113330540235
7656020031336
oct144567106777
937806426515
1013520113151
11580882a136
122753a3767b
13137607986c
14923878d1d
15541e3e6bb
hex325dc8dff

13520113151 has 4 divisors (see below), whose sum is σ = 13520632512. Its totient is φ = 13519593792.

The previous prime is 13520113097. The next prime is 13520113163. The reversal of 13520113151 is 15131102531.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13520113151 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13520113181) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 218450 + ... + 273423.

It is an arithmetic number, because the mean of its divisors is an integer number (3380158128).

Almost surely, 213520113151 is an apocalyptic number.

13520113151 is a deficient number, since it is larger than the sum of its proper divisors (519361).

13520113151 is an equidigital number, since it uses as much as digits as its factorization.

13520113151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 519360.

The product of its (nonzero) digits is 450, while the sum is 23.

Adding to 13520113151 its reverse (15131102531), we get a palindrome (28651215682).

The spelling of 13520113151 in words is "thirteen billion, five hundred twenty million, one hundred thirteen thousand, one hundred fifty-one".

Divisors: 1 27487 491873 13520113151