Base | Representation |
---|---|
bin | 11001001011101110… |
… | …01000110111111111 |
3 | 1021220020110220120112 |
4 | 30211313020313333 |
5 | 210142122110101 |
6 | 10113330540235 |
7 | 656020031336 |
oct | 144567106777 |
9 | 37806426515 |
10 | 13520113151 |
11 | 580882a136 |
12 | 2753a3767b |
13 | 137607986c |
14 | 923878d1d |
15 | 541e3e6bb |
hex | 325dc8dff |
13520113151 has 4 divisors (see below), whose sum is σ = 13520632512. Its totient is φ = 13519593792.
The previous prime is 13520113097. The next prime is 13520113163. The reversal of 13520113151 is 15131102531.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13520113151 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13520113181) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 218450 + ... + 273423.
It is an arithmetic number, because the mean of its divisors is an integer number (3380158128).
Almost surely, 213520113151 is an apocalyptic number.
13520113151 is a deficient number, since it is larger than the sum of its proper divisors (519361).
13520113151 is an equidigital number, since it uses as much as digits as its factorization.
13520113151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 519360.
The product of its (nonzero) digits is 450, while the sum is 23.
Adding to 13520113151 its reverse (15131102531), we get a palindrome (28651215682).
The spelling of 13520113151 in words is "thirteen billion, five hundred twenty million, one hundred thirteen thousand, one hundred fifty-one".
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