Base | Representation |
---|---|
bin | 1100010010111111000011… |
… | …1011100000010111100111 |
3 | 1202212112021020200001101210 |
4 | 3010233300323200113213 |
5 | 3233004040334231211 |
6 | 44431050401322503 |
7 | 2563544512414533 |
oct | 304576073402747 |
9 | 52775236601353 |
10 | 13520304211431 |
11 | 4342a24287816 |
12 | 16243aa636433 |
13 | 770c61524784 |
14 | 34a559abcbc3 |
15 | 186a62ac79a6 |
hex | c4bf0ee05e7 |
13520304211431 has 4 divisors (see below), whose sum is σ = 18027072281912. Its totient is φ = 9013536140952.
The previous prime is 13520304211387. The next prime is 13520304211457. The reversal of 13520304211431 is 13411240302531.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 13520304211431 - 211 = 13520304209383 is a prime.
It is a super-2 number, since 2×135203042114312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13520304411431) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2253384035236 + ... + 2253384035241.
It is an arithmetic number, because the mean of its divisors is an integer number (4506768070478).
Almost surely, 213520304211431 is an apocalyptic number.
13520304211431 is a deficient number, since it is larger than the sum of its proper divisors (4506768070481).
13520304211431 is an equidigital number, since it uses as much as digits as its factorization.
13520304211431 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4506768070480.
The product of its (nonzero) digits is 8640, while the sum is 30.
Adding to 13520304211431 its reverse (13411240302531), we get a palindrome (26931544513962).
The spelling of 13520304211431 in words is "thirteen trillion, five hundred twenty billion, three hundred four million, two hundred eleven thousand, four hundred thirty-one".
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