Base | Representation |
---|---|
bin | 11001001011111001… |
… | …00111111110001001 |
3 | 1021220100011222021010 |
4 | 30211330213332021 |
5 | 210143004114431 |
6 | 10113421434133 |
7 | 656035201122 |
oct | 144574477611 |
9 | 37810158233 |
10 | 13521551241 |
11 | 5809621640 |
12 | 275440b949 |
13 | 13764612c3 |
14 | 923b31049 |
15 | 542125846 |
hex | 325f27f89 |
13521551241 has 8 divisors (see below), whose sum is σ = 19667710944. Its totient is φ = 8194879520.
The previous prime is 13521551237. The next prime is 13521551249. The reversal of 13521551241 is 14215512531.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13521551241 - 22 = 13521551237 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13521551199 and 13521551208.
It is not an unprimeable number, because it can be changed into a prime (13521551249) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 204871956 + ... + 204872021.
It is an arithmetic number, because the mean of its divisors is an integer number (2458463868).
Almost surely, 213521551241 is an apocalyptic number.
13521551241 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
13521551241 is a deficient number, since it is larger than the sum of its proper divisors (6146159703).
13521551241 is a wasteful number, since it uses less digits than its factorization.
13521551241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 409743991.
The product of its digits is 6000, while the sum is 30.
The spelling of 13521551241 in words is "thirteen billion, five hundred twenty-one million, five hundred fifty-one thousand, two hundred forty-one".
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