13523400133 has 2 divisors, whose sum is σ = 13523400134. Its totient is φ = 13523400132.

The previous prime is 13523400127. The next prime is 13523400167. The reversal of 13523400133 is 33100432531.

13523400133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12108361444 + 1415038689 = 110038^2 + 37617^2 .

It is an emirp because it is prime and its reverse (33100432531) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13523400133 - 2⁵ = 13523400101 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13523400098 and 13523400107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13523400733) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6761700066 + 6761700067.

It is an arithmetic number, because the mean of its divisors is an integer number (6761700067).

Almost surely, 2^13523400133 is an apocalyptic number.

It is an amenable number.

13523400133 is a deficient number, since it is larger than the sum of its proper divisors (1).

13523400133 is an equidigital number, since it uses as much as digits as its factorization.

13523400133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3240, while the sum is 25.

Adding to 13523400133 its reverse (33100432531), we get a palindrome (46623832664).

The spelling of 13523400133 in words is "thirteen billion, five hundred twenty-three million, four hundred thousand, one hundred thirty-three".