1352340161 has 2 divisors, whose sum is σ = 1352340162. Its totient is φ = 1352340160.

The previous prime is 1352340149. The next prime is 1352340163. The reversal of 1352340161 is 1610432531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1114224400 + 238115761 = 33380^2 + 15431^2 .

It is a cyclic number.

It is not a de Polignac number, because 1352340161 - 2⁶ = 1352340097 is a prime.

It is a super-2 number, since 2×1352340161² = 3657647822107011842, which contains 22 as substring.

It is a Sophie Germain prime.

Together with 1352340163, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 1352340161.

It is not a weakly prime, because it can be changed into another prime (1352340163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 676170080 + 676170081.

It is an arithmetic number, because the mean of its divisors is an integer number (676170081).

Almost surely, 2^1352340161 is an apocalyptic number.

It is an amenable number.

1352340161 is a deficient number, since it is larger than the sum of its proper divisors (1).

1352340161 is an equidigital number, since it uses as much as digits as its factorization.

1352340161 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2160, while the sum is 26.

The square root of 1352340161 is about 36774.1779105937. The cubic root of 1352340161 is about 1105.8476903426.

Adding to 1352340161 its reverse (1610432531), we get a palindrome (2962772692).

The spelling of 1352340161 in words is "one billion, three hundred fifty-two million, three hundred forty thousand, one hundred sixty-one".