Base | Representation |
---|---|
bin | 11001001100001111… |
… | …00100100110101011 |
3 | 1021220112120202212210 |
4 | 30212013210212223 |
5 | 210144222433120 |
6 | 10114003140203 |
7 | 656101452636 |
oct | 144607444653 |
9 | 37815522783 |
10 | 13524421035 |
11 | 5810201774 |
12 | 2755374663 |
13 | 1376c275c8 |
14 | 92427ac1d |
15 | 5424e0ce0 |
hex | 3261e49ab |
13524421035 has 16 divisors (see below), whose sum is σ = 21640534560. Its totient is φ = 7212537600.
The previous prime is 13524420979. The next prime is 13524421087. The reversal of 13524421035 is 53012442531.
13524421035 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13524421035 - 26 = 13524420971 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13524420993 and 13524421011.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 364335 + ... + 399735.
It is an arithmetic number, because the mean of its divisors is an integer number (1352533410).
Almost surely, 213524421035 is an apocalyptic number.
13524421035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13524421035 is a deficient number, since it is larger than the sum of its proper divisors (8116113525).
13524421035 is a wasteful number, since it uses less digits than its factorization.
13524421035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 60878.
The product of its (nonzero) digits is 14400, while the sum is 30.
Adding to 13524421035 its reverse (53012442531), we get a palindrome (66536863566).
The spelling of 13524421035 in words is "thirteen billion, five hundred twenty-four million, four hundred twenty-one thousand, thirty-five".
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