Base | Representation |
---|---|
bin | 10011101011100111101… |
… | …010100010101100100111 |
3 | 11210022001111102221201122 |
4 | 103223213222202230213 |
5 | 134124413120420012 |
6 | 2513155522244155 |
7 | 166500240612161 |
oct | 23534752425447 |
9 | 4708044387648 |
10 | 1352506420007 |
11 | 48165a683736 |
12 | 19a15b7b665b |
13 | 9a705203812 |
14 | 49666b1b931 |
15 | 252ad862e72 |
hex | 13ae7aa2b27 |
1352506420007 has 4 divisors (see below), whose sum is σ = 1357285594920. Its totient is φ = 1347727245096.
The previous prime is 1352506419997. The next prime is 1352506420033. The reversal of 1352506420007 is 7000246052531.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1352506420007 - 24 = 1352506419991 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1352506420087) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2389587032 + ... + 2389587597.
It is an arithmetic number, because the mean of its divisors is an integer number (339321398730).
Almost surely, 21352506420007 is an apocalyptic number.
1352506420007 is a deficient number, since it is larger than the sum of its proper divisors (4779174913).
1352506420007 is an equidigital number, since it uses as much as digits as its factorization.
1352506420007 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4779174912.
The product of its (nonzero) digits is 50400, while the sum is 35.
The spelling of 1352506420007 in words is "one trillion, three hundred fifty-two billion, five hundred six million, four hundred twenty thousand, seven".
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