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13525135433 = 47163210831
BaseRepresentation
bin11001001100010100…
…10011000001001001
31021220120221001211222
430212022103001021
5210144413313213
610114030331425
7656110516505
oct144612230111
937816831758
1013525135433
11581064a487
122755659b75
131377117824
149243c5305
155425d2808
hex326293049

13525135433 has 12 divisors (see below), whose sum is σ = 13899449088. Its totient is φ = 13154941080.

The previous prime is 13525135423. The next prime is 13525135439. The reversal of 13525135433 is 33453152531.

It is a happy number.

It is not a de Polignac number, because 13525135433 - 26 = 13525135369 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13525135393 and 13525135402.

It is not an unprimeable number, because it can be changed into a prime (13525135439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1243328 + ... + 1254158.

It is an arithmetic number, because the mean of its divisors is an integer number (1158287424).

Almost surely, 213525135433 is an apocalyptic number.

It is an amenable number.

13525135433 is a deficient number, since it is larger than the sum of its proper divisors (374313655).

13525135433 is an equidigital number, since it uses as much as digits as its factorization.

13525135433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11204 (or 11041 counting only the distinct ones).

The product of its digits is 81000, while the sum is 35.

Adding to 13525135433 its reverse (33453152531), we get a palindrome (46978287964).

The spelling of 13525135433 in words is "thirteen billion, five hundred twenty-five million, one hundred thirty-five thousand, four hundred thirty-three".

Divisors: 1 47 163 7661 10831 26569 509057 1248743 1765453 82976291 287768839 13525135433