Base | Representation |
---|---|
bin | 11001001100010110… |
… | …10011111000111111 |
3 | 1021220121102120100101 |
4 | 30212023103320333 |
5 | 210200000314101 |
6 | 10114040141531 |
7 | 656113004263 |
oct | 144613237077 |
9 | 37817376311 |
10 | 13525401151 |
11 | 5810811089 |
12 | 27557678a7 |
13 | 13771ab762 |
14 | 9244540a3 |
15 | 542636401 |
hex | 3262d3e3f |
13525401151 has 4 divisors (see below), whose sum is σ = 13574229592. Its totient is φ = 13476572712.
The previous prime is 13525401139. The next prime is 13525401167. The reversal of 13525401151 is 15110452531.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 15110452531 = 23 ⋅656976197.
It is a cyclic number.
It is not a de Polignac number, because 13525401151 - 219 = 13524876863 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13525401181) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24413805 + ... + 24414358.
It is an arithmetic number, because the mean of its divisors is an integer number (3393557398).
Almost surely, 213525401151 is an apocalyptic number.
13525401151 is a deficient number, since it is larger than the sum of its proper divisors (48828441).
13525401151 is an equidigital number, since it uses as much as digits as its factorization.
13525401151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 48828440.
The product of its (nonzero) digits is 3000, while the sum is 28.
Adding to 13525401151 its reverse (15110452531), we get a palindrome (28635853682).
The spelling of 13525401151 in words is "thirteen billion, five hundred twenty-five million, four hundred one thousand, one hundred fifty-one".
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